Incazelo kanye nezakhiwo ze-median kanxantathu ongakwesokudla

Kulesi sihloko, sizocubungula incazelo kanye nezakhiwo ze-median kanxantathu ongakwesokudla odonswa ku-hypotenuse. Sizophinde sihlaziye isibonelo sokuxazulula inkinga ukuze sihlanganise indaba yetiyori.

Inquma i-median kanxantathu ongakwesokudla

Median ingxenye yomugqa ehlanganisa i-vertex kanxantathu nendawo emaphakathi ngakolunye uhlangothi.

Unxantathu wesokudla ingunxantathu lapho enye yama-engeli ilungile (90°) kanti amanye amabili ashubile (<90°).

Izici ze-median kanxantathu ongakwesokudla

Impahla 1

I-Median (AD) kunxantathu ongakwesokudla odwetshwe ku-vertex ye-engeli engakwesokudla (∠I-LACi-hypotenuse (BC) ingxenye ye-hypotenuse.

• BC = 2AD
• AD = BD = DC

Umphumela: Uma i-median ilingana nengxenye yohlangothi oludonswe kulo, khona-ke lolu hlangothi luyi-hypotenuse, futhi unxantathu u-angle kwesokudla.

Impahla 2

I-median edonselwa ku-hypotenuse kanxantathu ongakwesokudla ilingana nengxenye yempande yesikwele yesamba sezikwele zemilenze.

Ngonxantathu wethu (bheka umfanekiso ongenhla):

Ilandela kusuka futhi Izakhiwo 1.

Impahla 3

I-median ewiswe ku-hypotenuse kanxantathu ongakwesokudla ilingana ne-radius yendilinga ezungezwe unxantathu.

Labo. BO kokubili i-median ne-radius.

Qaphela: Kusebenza futhi kunxantathu ongakwesokudla, kungakhathaliseki ukuthi hlobo luni lukanxantathu.

Isibonelo senkinga

Ubude be-median edwetshiwe ku-hypotenuse kanxantathu ongakwesokudla buyi-10 cm. Futhi omunye umlenze 12 cm. Thola i-perimeter kanxantathu.

Isixazululo

I-hypotenuse kanxantathu, ngokulandelayo kusuka Izakhiwo 1, kabili i-median. Labo. ilingana: 10 cm ⋅ 2 = 20 cm.

Ukusebenzisa i-theorem ye-Pythagorean, sithola ubude bomlenze wesibili (siwuthatha njenge "B", umlenze odumile - we "kuya", hypotenuse - for "No"):

b² =c² - futhi² = 20² - 12² = 256.

Ngenxa yalokho, i- b = 16cm.

Manje sesiyazi ubude bazo zonke izinhlangothi futhi singakwazi ukubala umjikelezo wesibalo:

P_△ = 12 cm + 16 cm + 20 cm = 48 cm.